The results of the following example was compared with the results of FIRBAL software, developed years ago at Ondrejov Observatory (Z. Ceplecha, private communication). The comparison is very good.
Fireball IT19980812 Year: 1998 Month: 8 Day: 12 UT: 21.820833 Observer 1 Lat: 45.412° Long. 12.3687° Quote: 10 m Start AR: 30.819° Start Dec: 47.220° End AR: 59.941° End Dec: 56.863° Duration: 3 s Observer 2 Lat: 46.203° Long. 14.569° Quote: 100 m Start AR: 258.637° Start Dec: 3.389° End AR: 239.875° End Dec: 8.812° Duration: 3 s Press "Trajectory". The output file is: =============================================================================================== FIREBALL ATMOSPHERIC TRAJECTORY - EARTH SPHERICAL MODELL Fireball V.6.0 DATA OVER THE OBSERVED TRAJECTORY POINTS OBSERVER 1 Distance between Observer 1 and his start trajectory point = 104.8 km Latitude of start point (degree) = 45.89 East Longitude of start point (degree) = 13.28 Height above sea level of start point = 55.44 km Trajectory inclination at start point(degree) = 19.44 Distance between Observer 1 and his end trajectory point = 104.1 km Latitude of end point (degree) = 46.13 East Longitude of end point (degree) = 13.01 Height above sea level of end point = 43.37 km Trajectory inclination at end point (degree) = 19.13 Trajectory Azimut at end point (N -> E) = 142.05 degree Lenght of the observed atmospheric trajectory = 36.52 km OBSERVER 2 Distance between Observer 2 and his start trajectory point = 120.4 km Latitude of start point (degree) = 45.69 East Longitude of start point (degree) = 13.50 Height above sea level of start point = 65.46 km Trajectory inclination at start point(degree) = 19.69 Distance between Observer 2 and his end trajectory point = 121.1 km Latitude of end point (degree) = 45.96 East Longitude of end point (degree) = 13.20 Height above sea level of end point = 51.85 km Trajectory inclination at end point (degree) = 19.35 Trajectory Azimut at end point (N -> E) = 142.18 degree Lenght of the observed atmospheric trajectory = 40.74 km Mean inclination above Earth surface = 19.41 degree Mean Azimut (N -> E) of the apparent radiant = 142.12 degree PARAMETERS OF THE FIREBALL ATMOSPHERIC TRAJECTORY Minimum height above Earth surface = 0.02 km Latitude of minimum height = 47.041 degree East Longitude of minimum height = 11.969 degree Trajectory inclination above Earth surface at minimum point = 17.98 degree Azimut (N -> E) of the apparent radiant at minimum point = 140.83 degree Mean geocentric velocity = 12.9 km/s ================================================================================================ Put "Mean velocity = 21.0" Press "Orbit". The output file is: ================================================================================================ FIREBALL ORBIT - DATE 12 8 1998 AT 21.821 UT Geographical coordinates of the minimum height point: Latitude = 47.041 degree, East Longitude = 11.968 degree Fireball Parameters Trajectory: Azimut of the apparent radiant = 140.83 degree Trajectory inclination = 17.98 degree Height above sea level = 0.00 km, Geocentric Velocity = 21.00 km/s Equatorial Coordinates of the Apparent Radiant (2000): Dec. = -16.05 degree, AR. = 339.14 degree Orbital Elements (2000): Semi-major axis = 1.080 UA Eccentricity = 0.553 Inclination = 9.38 degree Longitude of the ascending node = 320.00 degree Argument of the perihelion = 118.09 degree True anomaly = 241.91 degree Orbital period = 409.979 mean solar day Mean anomaly = 307.93 degree Julianus dies of perihelion passage = 2450687.729 Perihelion distance = 0.482 UA Aphelion distance = 1.678 UA Eliocentric velocity at 1 UA from Sun = 30.5 km/s Ecliptic and Equatorial Coordinates of the true radiant: Ecliptic Coordinates (2000) Lat. = -7.81 degree, Long. = 263.79 degree Equatorial Coordinates (2000) Dec. = -31.10 degree, AR. = 262.82 degree ==============================================================================================
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